(3)/(y)+(2/7)=(7)/(7y)

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Solution for (3)/(y)+(2/7)=(7)/(7y) equation: 


D( y )

y = 0

7*y = 0

y = 0

y = 0

7*y = 0

7*y = 0

7*y = 0 // : 7

y = 0

y in (-oo:0) U (0:+oo)

3/y+2/7 = 7/(7*y) // - 7/(7*y)

3/y-(7/(7*y))+2/7 = 0

3/y-y^-1+2/7 = 0

2*y^-1 = -2/7 // : 2

y^-1 = -1/7

-1 < 0

1/(y^1) = -1/7 // * y^1

1 = -1/7*y^1 // : -1/7

-7 = y^1

y = -7

y = -7

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