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(3)1/3p=9(3)
We move all terms to the left:
(3)1/3p-(9(3))=0
Domain of the equation: 3p!=0determiningTheFunctionDomain 31/3p-93=0
p!=0/3
p!=0
p∈R
We multiply all the terms by the denominator
-93*3p+31=0
Wy multiply elements
-279p+31=0
We move all terms containing p to the left, all other terms to the right
-279p=-31
p=-31/-279
p=1/9
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