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(3)=(2x^2+5x-7)
We move all terms to the left:
(3)-((2x^2+5x-7))=0
We calculate terms in parentheses: -((2x^2+5x-7)), so:We get rid of parentheses
(2x^2+5x-7)
We get rid of parentheses
2x^2+5x-7
Back to the equation:
-(2x^2+5x-7)
-2x^2-5x+7+3=0
We add all the numbers together, and all the variables
-2x^2-5x+10=0
a = -2; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·(-2)·10
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{105}}{2*-2}=\frac{5-\sqrt{105}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{105}}{2*-2}=\frac{5+\sqrt{105}}{-4} $
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