(3*3)+(4*4)=(x*x)

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Solution for (3*3)+(4*4)=(x*x) equation:



(3*3)+(4*4)=(x*x)
We move all terms to the left:
(3*3)+(4*4)-((x*x))=0
We add all the numbers together, and all the variables
-((+x*x))+9+16=0
We add all the numbers together, and all the variables
-((+x*x))+25=0
We calculate terms in parentheses: -((+x*x)), so:
(+x*x)
We get rid of parentheses
x*x
Wy multiply elements
x^2
Back to the equation:
-(x^2)
We add all the numbers together, and all the variables
-1x^2+25=0
a = -1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-1)·25
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*-1}=\frac{-10}{-2} =+5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*-1}=\frac{10}{-2} =-5 $

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