(3*6i)/(4i+-2i)=Z

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Solution for (3*6i)/(4i+-2i)=Z equation: 



(3*6i)/(4i+-2i)=

We move all terms to the left:

(3*6i)/(4i+-2i)-()=0



Domain of the equation: (4i+-2i)!=0

i∈R



We add all the numbers together, and all the variables

(+3*6i)/(+2i)-()=0

We add all the numbers together, and all the variables

(+3*6i)/(+2i)=0

We multiply all the terms by the denominator


(+3*6i)=0

We get rid of parentheses

3*6i=0

Wy multiply elements

18i=0

i=0/18

i=0

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