(3*x*x)+(4*x/2)=56

Solution for (3*x*x)+(4*x/2)=56 equation:

(3x*x)+(4x/2)=56

We move all terms to the left:

(3x*x)+(4x/2)-(56)=0

We add all the numbers together, and all the variables

(+3x*x)+(+4x/2)-56=0

We get rid of parentheses

3x*x+4x/2-56=0

We multiply all the terms by the denominator


(3x*x)*2+4x-56*2=0

We add all the numbers together, and all the variables

(+3x*x)*2+4x-56*2=0

We add all the numbers together, and all the variables

4x+(+3x*x)*2-112=0

We multiply parentheses

6x^2+4x-112=0

a = 6; b = 4; c = -112;
Δ = b2-4ac
Δ = 42-4·6·(-112)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-52}{2*6}=\frac{-56}{12}
=-4+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+52}{2*6}=\frac{48}{12}
=4
$