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(3x+6)/3-(4x)/x-3-(x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-1x+(3x+6)/3-4x/x-3=0
We calculate fractions
-1x+(3x^2+6x)/3x+(-12x)/3x-3=0
We multiply all the terms by the denominator
-1x*3x+(3x^2+6x)+(-12x)-3*3x=0
Wy multiply elements
-3x^2+(3x^2+6x)+(-12x)-9x=0
We get rid of parentheses
-3x^2+3x^2+6x-12x-9x=0
We add all the numbers together, and all the variables
-15x=0
x=0/-15
x=0
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