(3*x-6)*(1/3)=(2-4*x)*(1/2)

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Solution for (3*x-6)*(1/3)=(2-4*x)*(1/2) equation: 



(3x-6)(1/3)=(2-4x)(1/2)

We move all terms to the left:

(3x-6)(1/3)-((2-4x)(1/2))=0

We add all the numbers together, and all the variables

(3x-6)(+1/3)-((-4x+2)(+1/2))=0

We multiply parentheses ..

(+3x^2-6*1/3)-((-4x+2)(+1/2))=0

We calculate fractions


3x^2/()+(-((-4x+2)3)/()=0



We calculate terms in parentheses: +(-((-4x+2)3)/(), so:

-((-4x+2)3)/(

We multiply all the terms by the denominator


-((-4x+2)3)



We calculate terms in parentheses: -((-4x+2)3), so:

(-4x+2)3

We multiply parentheses

-12x+6

Back to the equation:

-(-12x+6)



We get rid of parentheses

12x-6

Back to the equation:

+(12x-6)



We get rid of parentheses

3x^2/()+12x-6=0

We multiply all the terms by the denominator


3x^2+12x*()-6*()=0

We add all the numbers together, and all the variables

3x^2+12x*()=0

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