(3+-3y)+3y=3

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Solution for (3+-3y)+3y=3 equation: 



(3+-3y)+3y=3

We move all terms to the left:

(3+-3y)+3y-(3)=0

We add all the numbers together, and all the variables

(-3y)+3y-3=0

We add all the numbers together, and all the variables

3y+(-3y)-3=0

We get rid of parentheses

3y-3y-3=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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