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(3+1/5x)=(x+2)
We move all terms to the left:
(3+1/5x)-((x+2))=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(1/5x+3)-((x+2))=0
We get rid of parentheses
1/5x-((x+2))+3=0
We multiply all the terms by the denominator
-(((x+2)))*5x+3*5x+1=0
Wy multiply elements
-(((x+2)))*5x+15x+1=0
We add all the numbers together, and all the variables
15x-(((x+2)))*5x+1=0
We move all terms containing x to the left, all other terms to the right
15x-(((x+2)))*5x=-1
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