(3+2i)(2+3i)=

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Solution for (3+2i)(2+3i)= equation:


Simplifying
(3 + 2i)(2 + 3i) = 0

Multiply (3 + 2i) * (2 + 3i)
(3(2 + 3i) + 2i * (2 + 3i)) = 0
((2 * 3 + 3i * 3) + 2i * (2 + 3i)) = 0
((6 + 9i) + 2i * (2 + 3i)) = 0
(6 + 9i + (2 * 2i + 3i * 2i)) = 0
(6 + 9i + (4i + 6i2)) = 0

Combine like terms: 9i + 4i = 13i
(6 + 13i + 6i2) = 0

Solving
6 + 13i + 6i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(3 + 2i)(2 + 3i) = 0

Subproblem 1

Set the factor '(3 + 2i)' equal to zero and attempt to solve: Simplifying 3 + 2i = 0 Solving 3 + 2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2i = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2i = 0 + -3 2i = 0 + -3 Combine like terms: 0 + -3 = -3 2i = -3 Divide each side by '2'. i = -1.5 Simplifying i = -1.5

Subproblem 2

Set the factor '(2 + 3i)' equal to zero and attempt to solve: Simplifying 2 + 3i = 0 Solving 2 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3i = 0 + -2 3i = 0 + -2 Combine like terms: 0 + -2 = -2 3i = -2 Divide each side by '3'. i = -0.6666666667 Simplifying i = -0.6666666667

Solution

i = {-1.5, -0.6666666667}

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