(3+2i)(3-2i)+(4-3i)/1+i

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Solution for (3+2i)(3-2i)+(4-3i)/1+i equation: 


i in (-oo:+oo)

(2*i+3)*(3-(2*i))+(4-(3*i))/1+i = 0

(2*i+3)*(3-2*i)-3*i+i+4 = 0

(2*i+3)*(3-2*i)-3*i+i+4 = 0

i-4*i^2-3*i+4+9 = 0

4-4*i^2-2*i+9 = 0

13-4*i^2-2*i = 0

13-4*i^2-2*i = 0

13-4*i^2-2*i = 0

DELTA = (-2)^2-(-4*4*13)

DELTA = 212

DELTA > 0

i = (212^(1/2)+2)/(-4*2) or i = (2-212^(1/2))/(-4*2)

i = (2*53^(1/2)+2)/(-8) or i = (2-2*53^(1/2))/(-8)

(i-((2*53^(1/2)+2)/(-8)))*(i-((2-2*53^(1/2))/(-8))) = 0

(i-((2*53^(1/2)+2)/(-8)))*(i-((2-2*53^(1/2))/(-8))) = 0

( i-((2*53^(1/2)+2)/(-8)) )

i-((2*53^(1/2)+2)/(-8)) = 0 // + (2*53^(1/2)+2)/(-8)

i = (2*53^(1/2)+2)/(-8)

( i-((2-2*53^(1/2))/(-8)) )

i-((2-2*53^(1/2))/(-8)) = 0 // + (2-2*53^(1/2))/(-8)

i = (2-2*53^(1/2))/(-8)

i in { (2*53^(1/2)+2)/(-8), (2-2*53^(1/2))/(-8) }

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