(3+2i)(3-2i)=0

Solution for (3+2i)(3-2i)=0 equation:

Simplifying
(3 + 2i)(3 + -2i) = 0

Multiply (3 + 2i) * (3 + -2i)
(3(3 + -2i) + 2i * (3 + -2i)) = 0
((3 * 3 + -2i * 3) + 2i * (3 + -2i)) = 0
((9 + -6i) + 2i * (3 + -2i)) = 0
(9 + -6i + (3 * 2i + -2i * 2i)) = 0
(9 + -6i + (6i + -4i2)) = 0

Combine like terms: -6i + 6i = 0
(9 + 0 + -4i2) = 0
(9 + -4i2) = 0

Solving
9 + -4i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -4i2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4i2 = 0 + -9
-4i2 = 0 + -9

Combine like terms: 0 + -9 = -9
-4i2 = -9

Divide each side by '-4'.
i2 = 2.25

Simplifying
i2 = 2.25

Take the square root of each side:
i = {-1.5, 1.5}