(3+2i)(x+yi)=-i

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Solution for (3+2i)(x+yi)=-i equation:


Simplifying
(3 + 2i)(x + yi) = -1i

Reorder the terms:
(3 + 2i)(iy + x) = -1i

Multiply (3 + 2i) * (iy + x)
(3(iy + x) + 2i * (iy + x)) = -1i
((iy * 3 + x * 3) + 2i * (iy + x)) = -1i
((3iy + 3x) + 2i * (iy + x)) = -1i
(3iy + 3x + (iy * 2i + x * 2i)) = -1i

Reorder the terms:
(3iy + 3x + (2ix + 2i2y)) = -1i
(3iy + 3x + (2ix + 2i2y)) = -1i

Reorder the terms:
(2ix + 3iy + 2i2y + 3x) = -1i
(2ix + 3iy + 2i2y + 3x) = -1i

Solving
2ix + 3iy + 2i2y + 3x = -1i

Solving for variable 'i'.

Reorder the terms:
i + 2ix + 3iy + 2i2y + 3x = -1i + i

Combine like terms: -1i + i = 0
i + 2ix + 3iy + 2i2y + 3x = 0

The solution to this equation could not be determined.

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