(3+2i)/5i

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Solution for (3+2i)/5i equation:


i in (-oo:+oo)

i*((2*i+3)/5) = 0

(i*(2*i+3))/5 = 0

( 2*i+3 )

2*i+3 = 0 // - 3

2*i = -3 // : 2

i = -3/2

( i )

i = 0

i in { -3/2, 0 }

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