(3+2x)x=160

Solution for (3+2x)x=160 equation:

(3+2x)x=160

We move all terms to the left:

(3+2x)x-(160)=0

We add all the numbers together, and all the variables

(2x+3)x-160=0

We multiply parentheses

2x^2+3x-160=0

a = 2; b = 3; c = -160;
Δ = b2-4ac
Δ = 32-4·2·(-160)
Δ = 1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1289}}{2*2}=\frac{-3-\sqrt{1289}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1289}}{2*2}=\frac{-3+\sqrt{1289}}{4}
$