(3+2y)/8=(1-y)/5

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Solution for (3+2y)/8=(1-y)/5 equation: 



(3+2y)/8=(1-y)/5

We move all terms to the left:

(3+2y)/8-((1-y)/5)=0

We add all the numbers together, and all the variables

(2y+3)/8-((-1y+1)/5)=0

We calculate fractions


2y/()+(-((-1y+1)*8)/()=0



We calculate terms in parentheses: +(-((-1y+1)*8)/(), so:

-((-1y+1)*8)/(

We multiply all the terms by the denominator


-((-1y+1)*8)



We calculate terms in parentheses: -((-1y+1)*8), so:

(-1y+1)*8

We multiply parentheses

-8y+8

Back to the equation:

-(-8y+8)



We get rid of parentheses

8y-8

Back to the equation:

+(8y-8)



We get rid of parentheses

2y/()+8y-8=0

We multiply all the terms by the denominator


2y+8y*()-8*()=0

We add all the numbers together, and all the variables

2y+8y*()=0

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