(3+2z)4=-(z-3)

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Solution for (3+2z)4=-(z-3) equation: 



(3+2z)4=-(z-3)

We move all terms to the left:

(3+2z)4-(-(z-3))=0

We add all the numbers together, and all the variables

(2z+3)4-(-(z-3))=0

We multiply parentheses

8z-(-(z-3))+12=0



We calculate terms in parentheses: -(-(z-3)), so:

-(z-3)

We get rid of parentheses

-z+3

We add all the numbers together, and all the variables

-1z+3

Back to the equation:

-(-1z+3)



We get rid of parentheses

8z+1z-3+12=0

We add all the numbers together, and all the variables

9z+9=0

We move all terms containing z to the left, all other terms to the right

9z=-9

z=-9/9

z=-1

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