(3+3)+(2z+2z)=5

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Solution for (3+3)+(2z+2z)=5 equation: 



(3+3)+(2z+2z)=5

We move all terms to the left:

(3+3)+(2z+2z)-(5)=0

determiningTheFunctionDomain
(2z+2z)-5+(3+3)=0

We add all the numbers together, and all the variables

(+4z)-5+6=0

We add all the numbers together, and all the variables

(+4z)+1=0

We get rid of parentheses

4z+1=0

We move all terms containing z to the left, all other terms to the right

4z=-1

z=-1/4

z=-1/4

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