(3+3b)*(2+3b)=

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Solution for (3+3b)*(2+3b)= equation:


Simplifying
(3 + 3b)(2 + 3b) = 0

Multiply (3 + 3b) * (2 + 3b)
(3(2 + 3b) + 3b * (2 + 3b)) = 0
((2 * 3 + 3b * 3) + 3b * (2 + 3b)) = 0
((6 + 9b) + 3b * (2 + 3b)) = 0
(6 + 9b + (2 * 3b + 3b * 3b)) = 0
(6 + 9b + (6b + 9b2)) = 0

Combine like terms: 9b + 6b = 15b
(6 + 15b + 9b2) = 0

Solving
6 + 15b + 9b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '3'.
3(2 + 5b + 3b2) = 0

Factor a trinomial.
3((1 + b)(2 + 3b)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(1 + b)' equal to zero and attempt to solve: Simplifying 1 + b = 0 Solving 1 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + b = 0 + -1 b = 0 + -1 Combine like terms: 0 + -1 = -1 b = -1 Simplifying b = -1

Subproblem 2

Set the factor '(2 + 3b)' equal to zero and attempt to solve: Simplifying 2 + 3b = 0 Solving 2 + 3b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3b = 0 + -2 3b = 0 + -2 Combine like terms: 0 + -2 = -2 3b = -2 Divide each side by '3'. b = -0.6666666667 Simplifying b = -0.6666666667

Solution

b = {-1, -0.6666666667}

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