(3+4*(a+2))/(a+2)=5

Solution for (3+4*(a+2))/(a+2)=5 equation:

(3+4(a+2))/(a+2)=5

We move all terms to the left:

(3+4(a+2))/(a+2)-(5)=0


Domain of the equation: (a+2)!=0

We move all terms containing a to the left, all other terms to the right

a!=-2

a∈R


We multiply all the terms by the denominator


(3+4(a+2))-5*(a+2)=0


We calculate terms in parentheses: +(3+4(a+2)), so:

3+4(a+2)

determiningTheFunctionDomain
4(a+2)+3

We multiply parentheses

4a+8+3

We add all the numbers together, and all the variables

4a+11

Back to the equation:

+(4a+11)


We multiply parentheses

(4a+11)-5a-10=0

We get rid of parentheses

4a-5a+11-10=0

We add all the numbers together, and all the variables

-1a+1=0

We move all terms containing a to the left, all other terms to the right

-a=-1

a=-1/-1

a=1