(3+4b)=(4+7b)

Solution for (3+4b)=(4+7b) equation:

(3+4b)=(4+7b)

We move all terms to the left:

(3+4b)-((4+7b))=0

We add all the numbers together, and all the variables

(4b+3)-((7b+4))=0

We get rid of parentheses

4b-((7b+4))+3=0


We calculate terms in parentheses: -((7b+4)), so:

(7b+4)

We get rid of parentheses

7b+4

Back to the equation:

-(7b+4)


We get rid of parentheses

4b-7b-4+3=0

We add all the numbers together, and all the variables

-3b-1=0

We move all terms containing b to the left, all other terms to the right

-3b=1

b=1/-3

b=-1/3