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(3+4j)/(5-2j)=0
Domain of the equation: (5-2j)!=0We add all the numbers together, and all the variables
We move all terms containing j to the left, all other terms to the right
-2j!=-5
j!=-5/-2
j!=2+1/2
j∈R
(4j+3)/(-2j+5)=0
We multiply all the terms by the denominator
(4j+3)=0
We get rid of parentheses
4j+3=0
We move all terms containing j to the left, all other terms to the right
4j=-3
j=-3/4
j=-3/4
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