(3+4x)(3-4x)=25

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Solution for (3+4x)(3-4x)=25 equation: 



(3+4x)(3-4x)=25

We move all terms to the left:

(3+4x)(3-4x)-(25)=0

We add all the numbers together, and all the variables

(4x+3)(-4x+3)-25=0

We multiply parentheses ..

(-16x^2+12x-12x+9)-25=0

We get rid of parentheses

-16x^2+12x-12x+9-25=0

We add all the numbers together, and all the variables

-16x^2-16=0

a = -16; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-16)·(-16)
Δ = -1024
Delta is less than zero, so there is no solution for the equation

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