(3+5,8x)(3-2,2x)=8x

Solution for (3+5,8x)(3-2,2x)=8x equation:

(3+5.8x)(3-2.2x)=8x

We move all terms to the left:

(3+5.8x)(3-2.2x)-(8x)=0

We add all the numbers together, and all the variables

(5.8x+3)(-2.2x+3)-8x=0

We add all the numbers together, and all the variables

-8x+(5.8x+3)(-2.2x+3)=0

We multiply parentheses ..

(-10x^2+15x-6x+9)-8x=0

We get rid of parentheses

-10x^2+15x-6x-8x+9=0

We add all the numbers together, and all the variables

-10x^2+x+9=0

a = -10; b = 1; c = +9;
Δ = b2-4ac
Δ = 12-4·(-10)·9
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*-10}=\frac{-20}{-20}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*-10}=\frac{18}{-20}
=-9/10
$