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(3+5x)(2-3x)=12-15x^2
We move all terms to the left:
(3+5x)(2-3x)-(12-15x^2)=0
We add all the numbers together, and all the variables
-(12-15x^2)+(5x+3)(-3x+2)=0
We get rid of parentheses
15x^2+(5x+3)(-3x+2)-12=0
We multiply parentheses ..
15x^2+(-15x^2+10x-9x+6)-12=0
We get rid of parentheses
15x^2-15x^2+10x-9x+6-12=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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