(3+i)z+2i=6i

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Solution for (3+i)z+2i=6i equation:


Simplifying
(3 + i) * z + 2i = 6i

Reorder the terms for easier multiplication:
z(3 + i) + 2i = 6i
(3 * z + i * z) + 2i = 6i

Reorder the terms:
(iz + 3z) + 2i = 6i
(iz + 3z) + 2i = 6i

Reorder the terms:
2i + iz + 3z = 6i

Solving
2i + iz + 3z = 6i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-6i' to each side of the equation.
2i + iz + -6i + 3z = 6i + -6i

Reorder the terms:
2i + -6i + iz + 3z = 6i + -6i

Combine like terms: 2i + -6i = -4i
-4i + iz + 3z = 6i + -6i

Combine like terms: 6i + -6i = 0
-4i + iz + 3z = 0

Add '-3z' to each side of the equation.
-4i + iz + 3z + -3z = 0 + -3z

Combine like terms: 3z + -3z = 0
-4i + iz + 0 = 0 + -3z
-4i + iz = 0 + -3z
Remove the zero:
-4i + iz = -3z

Combine like terms: -3z + 3z = 0
-4i + iz + 3z = 0

The solution to this equation could not be determined.

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