(3+q)+(q-6)+q=63

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Solution for (3+q)+(q-6)+q=63 equation: 



(3+q)+(q-6)+q=63

We move all terms to the left:

(3+q)+(q-6)+q-(63)=0

We add all the numbers together, and all the variables

(q+3)+(q-6)+q-63=0

We add all the numbers together, and all the variables

q+(q+3)+(q-6)-63=0

We get rid of parentheses

q+q+q+3-6-63=0

We add all the numbers together, and all the variables

3q-66=0

We move all terms containing q to the left, all other terms to the right

3q=66

q=66/3

q=22

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