(3+x)(2x=1)

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Solution for (3+x)(2x=1) equation:



(3+x)(2x=1)
We move all terms to the left:
(3+x)(2x-(1))=0
We add all the numbers together, and all the variables
(x+3)(2x-1)=0
We multiply parentheses ..
(+2x^2-1x+6x-3)=0
We get rid of parentheses
2x^2-1x+6x-3=0
We add all the numbers together, and all the variables
2x^2+5x-3=0
a = 2; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·2·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*2}=\frac{-12}{4} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*2}=\frac{2}{4} =1/2 $

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