(3+x)+(2x-5)+x=78

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Solution for (3+x)+(2x-5)+x=78 equation: 



(3+x)+(2x-5)+x=78

We move all terms to the left:

(3+x)+(2x-5)+x-(78)=0

We add all the numbers together, and all the variables

(x+3)+(2x-5)+x-78=0

We add all the numbers together, and all the variables

x+(x+3)+(2x-5)-78=0

We get rid of parentheses

x+x+2x+3-5-78=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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