(3+x)+(2x-5)=78

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Solution for (3+x)+(2x-5)=78 equation:



(3+x)+(2x-5)=78
We move all terms to the left:
(3+x)+(2x-5)-(78)=0
We add all the numbers together, and all the variables
(x+3)+(2x-5)-78=0
We get rid of parentheses
x+2x+3-5-78=0
We add all the numbers together, and all the variables
3x-80=0
We move all terms containing x to the left, all other terms to the right
3x=80
x=80/3
x=26+2/3

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