(3+x)-2=(28-6x)-(9+2x)

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Solution for (3+x)-2=(28-6x)-(9+2x) equation: 



(3+x)-2=(28-6x)-(9+2x)

We move all terms to the left:

(3+x)-2-((28-6x)-(9+2x))=0

We add all the numbers together, and all the variables

(x+3)-((-6x+28)-(2x+9))-2=0

We get rid of parentheses

x-((-6x+28)-(2x+9))+3-2=0



We calculate terms in parentheses: -((-6x+28)-(2x+9)), so:

(-6x+28)-(2x+9)

We get rid of parentheses

-6x-2x+28-9

We add all the numbers together, and all the variables

-8x+19

Back to the equation:

-(-8x+19)



We add all the numbers together, and all the variables

x-(-8x+19)+1=0

We get rid of parentheses

x+8x-19+1=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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