(3+x)10+x=10x+(3+x)-36

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Solution for (3+x)10+x=10x+(3+x)-36 equation: 



(3+x)10+x=10x+(3+x)-36

We move all terms to the left:

(3+x)10+x-(10x+(3+x)-36)=0

We add all the numbers together, and all the variables

(x+3)10+x-(10x+(x+3)-36)=0

We add all the numbers together, and all the variables

x+(x+3)10-(10x+(x+3)-36)=0

We multiply parentheses

x+10x-(10x+(x+3)-36)+30=0



We calculate terms in parentheses: -(10x+(x+3)-36), so:

10x+(x+3)-36

We get rid of parentheses

10x+x+3-36

We add all the numbers together, and all the variables

11x-33

Back to the equation:

-(11x-33)



We add all the numbers together, and all the variables

11x-(11x-33)+30=0

We get rid of parentheses

11x-11x+33+30=0

We add all the numbers together, and all the variables

63!=0

There is no solution for this equation

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