(3+x)6x-8=-14

Solution for (3+x)6x-8=-14 equation:

(3+x)6x-8=-14

We move all terms to the left:

(3+x)6x-8-(-14)=0

We add all the numbers together, and all the variables

(x+3)6x-8-(-14)=0

We add all the numbers together, and all the variables

(x+3)6x+6=0

We multiply parentheses

6x^2+18x+6=0

a = 6; b = 18; c = +6;
Δ = b2-4ac
Δ = 182-4·6·6
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{5}}{2*6}=\frac{-18-6\sqrt{5}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{5}}{2*6}=\frac{-18+6\sqrt{5}}{12}
$