(3+x)=3(x-3)-4

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Solution for (3+x)=3(x-3)-4 equation: 



(3+x)=3(x-3)-4

We move all terms to the left:

(3+x)-(3(x-3)-4)=0

We add all the numbers together, and all the variables

(x+3)-(3(x-3)-4)=0

We get rid of parentheses

x-(3(x-3)-4)+3=0



We calculate terms in parentheses: -(3(x-3)-4), so:

3(x-3)-4

We multiply parentheses

3x-9-4

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We get rid of parentheses

x-3x+13+3=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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