(3+y)/5=(2y+8)/12

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Solution for (3+y)/5=(2y+8)/12 equation: 



(3+y)/5=(2y+8)/12

We move all terms to the left:

(3+y)/5-((2y+8)/12)=0

We add all the numbers together, and all the variables

(y+3)/5-((2y+8)/12)=0

We calculate fractions


y/()+(-((2y+8)*5)/()=0



We calculate terms in parentheses: +(-((2y+8)*5)/(), so:

-((2y+8)*5)/(

We multiply all the terms by the denominator


-((2y+8)*5)



We calculate terms in parentheses: -((2y+8)*5), so:

(2y+8)*5

We multiply parentheses

10y+40

Back to the equation:

-(10y+40)



We get rid of parentheses

-10y-40

Back to the equation:

+(-10y-40)



We get rid of parentheses

y/()-10y-40=0

We multiply all the terms by the denominator


y-10y*()-40*()=0

We add all the numbers together, and all the variables

y-10y*()=0

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