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(3+z)(5z+8)=0
We add all the numbers together, and all the variables
(z+3)(5z+8)=0
We multiply parentheses ..
(+5z^2+8z+15z+24)=0
We get rid of parentheses
5z^2+8z+15z+24=0
We add all the numbers together, and all the variables
5z^2+23z+24=0
a = 5; b = 23; c = +24;
Δ = b2-4ac
Δ = 232-4·5·24
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*5}=\frac{-30}{10} =-3 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*5}=\frac{-16}{10} =-1+3/5 $
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