(3-10i)=(15-20i)

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Solution for (3-10i)=(15-20i) equation: 



(3-10i)=(15-20i)

We move all terms to the left:

(3-10i)-((15-20i))=0

We add all the numbers together, and all the variables

(-10i+3)-((-20i+15))=0

We get rid of parentheses

-10i-((-20i+15))+3=0



We calculate terms in parentheses: -((-20i+15)), so:

(-20i+15)

We get rid of parentheses

-20i+15

Back to the equation:

-(-20i+15)



We get rid of parentheses

-10i+20i-15+3=0

We add all the numbers together, and all the variables

10i-12=0

We move all terms containing i to the left, all other terms to the right

10i=12

i=12/10

i=1+1/5

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