(3-2(X+1))=3X+2(x+2x))

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Solution for (3-2(X+1))=3X+2(x+2x)) equation: 



(3-2(X+1))=3X+2(X+2X))

We move all terms to the left:

(3-2(X+1))-(3X+2(X+2X)))=0

We add all the numbers together, and all the variables

(3-2(X+1))-(3X+2(+3X)))=0



We calculate terms in parentheses: +(3-2(X+1)), so:

3-2(X+1)

determiningTheFunctionDomain
-2(X+1)+3

We multiply parentheses

-2X-2+3

We add all the numbers together, and all the variables

-2X+1

Back to the equation:

+(-2X+1)





We calculate terms in parentheses: -(3X+2(+3X))), so:

3X+2(+3X))

We multiply parentheses

3X+6X

We add all the numbers together, and all the variables

9X

Back to the equation:

-(9X)



We add all the numbers together, and all the variables

-9X+(-2X+1)=0

We get rid of parentheses

-9X-2X+1=0

We add all the numbers together, and all the variables

-11X+1=0

We move all terms containing X to the left, all other terms to the right

-11X=-1

X=-1/-11

X=1/11

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