(3-2i)(3+2i)=0

Solution for (3-2i)(3+2i)=0 equation:

Simplifying
(3 + -2i)(3 + 2i) = 0

Multiply (3 + -2i) * (3 + 2i)
(3(3 + 2i) + -2i * (3 + 2i)) = 0
((3 * 3 + 2i * 3) + -2i * (3 + 2i)) = 0
((9 + 6i) + -2i * (3 + 2i)) = 0
(9 + 6i + (3 * -2i + 2i * -2i)) = 0
(9 + 6i + (-6i + -4i2)) = 0

Combine like terms: 6i + -6i = 0
(9 + 0 + -4i2) = 0
(9 + -4i2) = 0

Solving
9 + -4i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -4i2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4i2 = 0 + -9
-4i2 = 0 + -9

Combine like terms: 0 + -9 = -9
-4i2 = -9

Divide each side by '-4'.
i2 = 2.25

Simplifying
i2 = 2.25

Take the square root of each side:
i = {-1.5, 1.5}