(3-2i)-(4+i)=0

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Solution for (3-2i)-(4+i)=0 equation: 



(3-2i)-(4+i)=0

We add all the numbers together, and all the variables

(-2i+3)-(i+4)=0

We get rid of parentheses

-2i-i+3-4=0

We add all the numbers together, and all the variables

-3i-1=0

We move all terms containing i to the left, all other terms to the right

-3i=1

i=1/-3

i=-1/3

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