(3-2x)(3-2x)=0

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Solution for (3-2x)(3-2x)=0 equation: 



(3-2x)(3-2x)=0

We add all the numbers together, and all the variables

(-2x+3)(-2x+3)=0

We multiply parentheses ..

(+4x^2-6x-6x+9)=0

We get rid of parentheses

4x^2-6x-6x+9=0

We add all the numbers together, and all the variables

4x^2-12x+9=0

a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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