(3-2x)*5+(2x-1)*(-3)=-4(2x+1)+30

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Solution for (3-2x)*5+(2x-1)*(-3)=-4(2x+1)+30 equation: 



(3-2x)*5+(2x-1)(-3)=-4(2x+1)+30

We move all terms to the left:

(3-2x)*5+(2x-1)(-3)-(-4(2x+1)+30)=0

We add all the numbers together, and all the variables

(-2x+3)*5+(2x-1)(-3)-(-4(2x+1)+30)=0

We multiply parentheses

-10x+(2x-1)(-3)-(-4(2x+1)+30)+15=0

We multiply parentheses ..

-10x+(-6x+3)-(-4(2x+1)+30)+15=0



We calculate terms in parentheses: -(-4(2x+1)+30), so:

-4(2x+1)+30

We multiply parentheses

-8x-4+30

We add all the numbers together, and all the variables

-8x+26

Back to the equation:

-(-8x+26)



We get rid of parentheses

-10x-6x+8x+3-26+15=0

We add all the numbers together, and all the variables

-8x-8=0

We move all terms containing x to the left, all other terms to the right

-8x=8

x=8/-8

x=-1

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