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(3-2x)/(2x+5)=3/11
We move all terms to the left:
(3-2x)/(2x+5)-(3/11)=0
Domain of the equation: (2x+5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-5
x!=-5/2
x!=-2+1/2
x∈R
(-2x+3)/(2x+5)-(+3/11)=0
We get rid of parentheses
(-2x+3)/(2x+5)-3/11=0
We calculate fractions
(-22x+33)/(22x+55)+(-6x-15)/(22x+55)=0
We multiply all the terms by the denominator
(-22x+33)+(-6x-15)=0
We get rid of parentheses
-22x-6x+33-15=0
We add all the numbers together, and all the variables
-28x+18=0
We move all terms containing x to the left, all other terms to the right
-28x=-18
x=-18/-28
x=9/14
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