(3-2x)/3=x-3/2-125/6

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Solution for (3-2x)/3=x-3/2-125/6 equation: 


x in (-oo:+oo)

(3-(2*x))/3 = x-(3/2)-(125/6) // - x-(3/2)-(125/6)

(3-(2*x))/3-x+3/2+125/6 = 0

(3-2*x)/3-x+3/2+125/6 = 0

(2*6*(3-2*x))/(2*3*6)+(2*3*6*(-x))/(2*3*6)+(6*3^2)/(2*3*6)+(2*3*125)/(2*3*6) = 0

2*6*(3-2*x)+2*3*6*(-x)+6*3^2+2*3*125 = 0

36-60*x+54+750 = 0

90-60*x+750 = 0

840-60*x = 0

(840-60*x)/(2*3*6) = 0

(840-60*x)/(2*3*6) = 0 // * 2*3*6

840-60*x = 0

840-60*x = 0 // - 840

-60*x = -840 // : -60

x = -840/(-60)

x = 14

x = 14

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