(3-2x)/5+8=(5x+2)/2-x

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Solution for (3-2x)/5+8=(5x+2)/2-x equation: 



(3-2x)/5+8=(5x+2)/2-x

We move all terms to the left:

(3-2x)/5+8-((5x+2)/2-x)=0



Domain of the equation: 2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

(-2x+3)/5-((5x+2)/2-x)+8=0

We calculate fractions


(-4x-x)-x)+5*2)+(-((5x+2)*5)/(-x)+5*2)+8+6)/(=0

We add all the numbers together, and all the variables

(-5x)-x)+5*2)+(-((5x+2)*5)/(-1x)+5*2)+8+6)/(=0

We get rid of parentheses

-5x-x)+5*2)+(-((5x+2)*5)/(-1x)+5*2)+8+6)/(=0

We multiply all the terms by the denominator


-5x*(-x)-((5x+2)*5)-1x)+5*2)+8+6)+5*2)+(=0



We calculate terms in parentheses: -((5x+2)*5), so:

(5x+2)*5

We multiply parentheses

25x+10

Back to the equation:

-(25x+10)



We add all the numbers together, and all the variables

-5x*(-1x)-(25x+10)-1x)+5*2)+8+6)+5*2)+(=0

We multiply parentheses

5x^2-(25x+10)-1x)+5*2)+8+6)+5*2)+(=0

We get rid of parentheses

5x^2-25x-1x)+5*2)+8+6)+5*2)+(-10=0

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