(3-2x)/5+8=(5x+2)/2-x

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Solution for (3-2x)/5+8=(5x+2)/2-x equation:



(3-2x)/5+8=(5x+2)/2-x
We move all terms to the left:
(3-2x)/5+8-((5x+2)/2-x)=0
Domain of the equation: 2-x)!=0
We move all terms containing x to the left, all other terms to the right
-x)!=-2
x!=-2/1
x!=-2
x∈R
We add all the numbers together, and all the variables
(-2x+3)/5-((5x+2)/2-x)+8=0
We calculate fractions
(-4x-x)-x)+5*2)+(-((5x+2)*5)/(-x)+5*2)+8+6)/(=0
We add all the numbers together, and all the variables
(-5x)-x)+5*2)+(-((5x+2)*5)/(-1x)+5*2)+8+6)/(=0
We get rid of parentheses
-5x-x)+5*2)+(-((5x+2)*5)/(-1x)+5*2)+8+6)/(=0
We multiply all the terms by the denominator
-5x*(-x)-((5x+2)*5)-1x)+5*2)+8+6)+5*2)+(=0
We calculate terms in parentheses: -((5x+2)*5), so:
(5x+2)*5
We multiply parentheses
25x+10
Back to the equation:
-(25x+10)
We add all the numbers together, and all the variables
-5x*(-1x)-(25x+10)-1x)+5*2)+8+6)+5*2)+(=0
We multiply parentheses
5x^2-(25x+10)-1x)+5*2)+8+6)+5*2)+(=0
We get rid of parentheses
5x^2-25x-1x)+5*2)+8+6)+5*2)+(-10=0

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