(3-2y)(2)=(14+4y)(-3)

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Solution for (3-2y)(2)=(14+4y)(-3) equation: 



(3-2y)(2)=(14+4y)(-3)

We move all terms to the left:

(3-2y)(2)-((14+4y)(-3))=0

We add all the numbers together, and all the variables

(-2y+3)2-((4y+14)(-3))=0

We multiply parentheses

-4y-((4y+14)(-3))+6=0

We multiply parentheses ..

-4y-((-12y-42))+6=0



We calculate terms in parentheses: -((-12y-42)), so:

(-12y-42)

We get rid of parentheses

-12y-42

Back to the equation:

-(-12y-42)



We get rid of parentheses

-4y+12y+42+6=0

We add all the numbers together, and all the variables

8y+48=0

We move all terms containing y to the left, all other terms to the right

8y=-48

y=-48/8

y=-6

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