(3-2y)=2(y+2)

Solution for (3-2y)=2(y+2) equation:

(3-2y)=2(y+2)

We move all terms to the left:

(3-2y)-(2(y+2))=0

We add all the numbers together, and all the variables

(-2y+3)-(2(y+2))=0

We get rid of parentheses

-2y-(2(y+2))+3=0


We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)


We get rid of parentheses

-2y-2y-4+3=0

We add all the numbers together, and all the variables

-4y-1=0

We move all terms containing y to the left, all other terms to the right

-4y=1

y=1/-4

y=-1/4