(3-2y2)=25

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Solution for (3-2y2)=25 equation: 



(3-2y^2)=25

We move all terms to the left:

(3-2y^2)-(25)=0

We get rid of parentheses

-2y^2+3-25=0

We add all the numbers together, and all the variables

-2y^2-22=0

a = -2; b = 0; c = -22;
Δ = b2-4ac
Δ = 02-4·(-2)·(-22)
Δ = -176
Delta is less than zero, so there is no solution for the equation

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