(3-3k)(3-3k)=0

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Solution for (3-3k)(3-3k)=0 equation: 



(3-3k)(3-3k)=0

We add all the numbers together, and all the variables

(-3k+3)(-3k+3)=0

We multiply parentheses ..

(+9k^2-9k-9k+9)=0

We get rid of parentheses

9k^2-9k-9k+9=0

We add all the numbers together, and all the variables

9k^2-18k+9=0

a = 9; b = -18; c = +9;
Δ = b2-4ac
Δ = -182-4·9·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{18}{18}=1$

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